tag:blogger.com,1999:blog-4214441415976328779.post3822324695329269996..comments2023-11-21T00:32:55.909-08:00Comments on CURRENT AFFAIRS 2012 (TRIVIA QUIZ): HARDEST LOGICAL REASONING QUIZ QUESTIONSVikas Ahlawat(Hi)http://www.blogger.com/profile/03921126217720780833noreply@blogger.comBlogger2125tag:blogger.com,1999:blog-4214441415976328779.post-45510578160840522642011-03-22T09:47:33.052-07:002011-03-22T09:47:33.052-07:00Answres
1.8/15 < n/(k + n) < 7/13
=> 13/...Answres<br />1.8/15 < n/(k + n) < 7/13<br /><br />=> 13/7 < 1 + k/n < 15/8<br /><br />=> 6/7 < k/n < 7/8<br /><br />=> Making denominator of upper bound and lower bond same =><br /><br />48/56 < k/n < 49/56<br /><br />=> 96/112 < k/n < 98/112<br /><br />=> smallest integral permissible value of k = 97.<br /><br />Now, obviously ...<br /><br />n =112 because beside this, 97/(112 +/- 1) will not satisfy the condition.<br /><br /><br />2answer.<br />Since all 10 digit numbers with distinct digits are divisible by 9 so the number is divisible by 9. And since 11111 and 9 are relatively prime, then number should be divisible by 9*11111 = 99999.<br /><br />Now, consider following number<br /><br />abcdefghij and what number 99999 must be multiplied by. It must be<br />larger than abcde, because abcde*100000 = abcde00000 < abcdefghij. It<br />can't be abcde+2 (or larger), because:<br /><br />99999*(abcde+2) = (100000-1)*(abcde+2) = abcde00000 + 199998 - abcde<br /><br />Looking at the 10000's digit of that, 0 + 9 - e would not require a borrow, regardless of the value of e. Therefore the 100000's digit would be e + 1, which doesn't equal the 100000's digit of abcdefghij.<br /><br />That implies that:<br /><br />abcdefghij = 99999*(abcde+1) = (100000-1)*(abcde+1)<br /><br />=> abcde00000 + fghij = abcde00000 + (99999 - abcde)<br /><br />=> fghij = 99999 - abcde<br /><br />which implies<br /><br />f = 9 - a<br />g = 9 - b<br />h = 9 - c<br />i = 9 - d<br />j = 9 - e<br /><br />Now a can not be 0, f can not be 9. => 9 possible values for a, => 8 possible values for b, Now, {a,b,g,f} are known, => 6 possible values of c and then h is known, => 4 possible values for d and then 'i' is known => 2 possible values for e and then j is known..<br /><br />So in total 9*8*6*4*2 = 3456 such numbers are possible.<br /><br /><br />3. 6<br /><br /><br /><br />4 Rs 112.50 <br /><br /><br /><br />5. let the number be 5x<br />now diff is given by (5*5x)-(5x/5) =25x-x = 24x<br />%change in the result = (diff/result)*100= (24x/25x)*100 =96 <br /><br /><br />6. 3<br /><br />7. 210,(Assume that every men eat equal quantity of food )<br />Now, 150 men can eat 45 days means 1 man can eat 6750 days.<br />after 10 days 1500 days of food will be finished.<br />remaining 5250 days of food is shared by 25 people<br /><br />thus 5250/25=210<br /><br /><br />8. Let (120) men = (200) children= x . that means 150 children=90 men<br /><br />now, x=(250) children+(men) y<br /><br />but 120 men=90 men+men(y)<br /><br />thus y=30 men<br /><br /><br />9. One cow eat 1 bag in 40 days. that means 40 cows need 40 bags for 40 daysVikas Ahlawat(Hi)https://www.blogger.com/profile/03921126217720780833noreply@blogger.comtag:blogger.com,1999:blog-4214441415976328779.post-31569962135608151612011-03-20T22:09:41.747-07:002011-03-20T22:09:41.747-07:00Please post the answers.Please post the answers.Unknownhttps://www.blogger.com/profile/04505851239499032389noreply@blogger.com